@Ellen艾艾子
2024-02-05 19:35
原文

太帅了受不了了!开导!🥵🥵🥵🥵(sinx)' = cosx (cosx)' = - sinx (secx)'=tanx·secx (cscx)'=-cotx·cscx (arcsinx)'=1/(1-x^2)^1/2 (arccosx)'=-1/(1-x^2)^1/2 ......不能导出来,给我积回去🥵🥵🥵∫x^udx=(x^u+1)/(u+1)+c3、∫1/xdx=ln|x|+c4、∫e^xdx=e^x+c......积不回去了,我要设啦...全文

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